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Divide: \( t > 2,400,000 / 120,000 = 20 \)
So after 21 years, it drops below. But the question asks when it *drop...
But numerically: \( t = 20 \) gives exactly 6M → needs to go below, so...
However, math solution: \( t > 20 \), so after 20 years it reaches 6M,...
Solve: \( 8,400,000 - 120,000t < 6,000,000 \Rightarrow t > 20 \) → so...
But precise answer: the number of years is 21.
However, standard is to report the integer value satisfying, so t = 21...
But let's compute:
At t=20: 8.4M - 1.2M×20 = 8.4M - 24M = negative? No: 120,000 × 20 = 2,...
At t=21: 120,000×21 = 2,520,000 → 8,400,000 - 2,520,000 = 5,880,000 <...

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