Solution: Simplify $ f(n) $ by factoring the numerator: $ n^3 - 8 = (n - 2)(n^2 + 2n + 4) $. Thus, $ f(n) = rac{(n - 2)(n^2 + 2n + 4)}{n - 2} = n^2 + 2n + 4 $ for $ n

Tue, 05 May 2026 14:21:35 +0000

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