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Home » Prime Insider Alert: Yahoo Finance Overnight Price Explodes Like Never! - Decision Point

Prime Insider Alert: Yahoo Finance Overnight Price Explodes Like Never! - Decision Point

📅 May 5, 2026 👤 scraface

May 05, 2026

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📌 Then $ x \equiv -3 \pmod{504} $, so $ x = 504k - 3 $.

📌 For $ x $ to be two-digit:

📌 \leq 504k - 3 \leq 99 \Rightarrow 13 \leq 504k \leq 102 \Rightarrow k = 0 \text{ or } 1

📌 Only $ k = 0 $ gives $ x = -3 $, $ k = 1 $ gives $ x = 501 $.

📌 No two-digit solution.

📌 But perhaps we made a misinterpretation. Let’s suppose the question means a number that is **three less than a common multiple** of $ 7, 8, 9 $, not necessarily the LCM.

📌 So $ x + 3 = \text{lcm}(7,8,9) \cdot k = 504k $.

📌 Still same result.

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\[ a^2 + b^2 = c^2 = 100 \]
We have two equations:
\( a^2 + b^2 = 100 \)
Using the identity \((a + b)^2 = a^2 + b^2 + 2ab\), we substitute:
\[ 14^2 = 100 + 2ab \]
\[ 196 = 100 + 2ab \]
\[ 2ab = 96 \]
\[ ab = 48 \]
Thus, the area of the triangle is:
\[ A = \frac{1}{2} \times 48 = 24 \]

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