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📅 May 4, 2026 👤 scraface

May 04, 2026

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But given it's $\sqrt{3}$, and since maximum of $\cos\theta$ is 1, no...
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = 2 \cos\theta \cos...
So $\cos\theta = \sqrt{3}$ — still impossible. Hence, original equatio...
Then $\cos\theta = 1 \Rightarrow \theta = 0^\circ$. But not minimal po...
Wait—what if the equation is:
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \sqrt{3} \cdot \co...
But that's identity. So instead, suppose the intended equation is:
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \sqrt{3}
\Rightarrow \cos\theta = \sqrt{3} \quad \text{(impossible)}
Thus, no solution. But to fix, suppose the equation is:

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