Solution: A regular hexagon can be divided into 6 equilateral triangles, each with side length 3 cm. The area of one equilateral triangle is $\frac{\sqrt{3}}{4} \times 3^2 = \frac{9\sqrt{3}}{4}$. The total area is $6 \times \frac{9\sqrt{3}}{4} = \frac{54\sqrt{3}}{4} = \frac{27\sqrt{3}}{2}$.

Sun, 03 May 2026 01:09:43 +0000

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