Solution: A regular octahedron has 8 equilateral triangular faces. The area of one face is $\frac{\sqrt{3}}{4} \times 4^2 = 4\sqrt{3}$. Total surface area: $8 \times 4\sqrt{3} = 32\sqrt{3}$ nm².

Sun, 03 May 2026 01:09:43 +0000

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