A train travels from City A to City B, a distance of 450 kilometers, at a constant speed. On the return trip, it travels 25% faster and takes 1 hour less. What was the trains speed from A to B?

Mon, 04 May 2026 00:29:00 +0000

A train travels from City A to City B, a distance of 450 kilometers, at a constant speed. On the return trip, it travels 25% faster and takes 1 hour less. What was the train’s speed from A to B? This steady-speed journey, taking a precise hour less on the return, has sparked curiosity across transport forums and data-driven travel communities. With growing interest in efficient rail networks and sustainable travel, this problem blends real-world logistics with everyday curiosity. Many users are drawn to understanding the dynamics of speed, time, and distance—especially in long-haul routes that shape regional commuting and intercity travel habits. The train’s steady 450-kilometer route means energy and timing depend directly on consistent velocity. The return leg, moving 25% faster, cuts travel time by an hour—highlighting how small shifts in speed can create meaningful changes at scale. Such questions reflect a broader trend in US transportation: a shift toward smarter, more efficient travel enabled by data and design. To address the query directly: the train’s speed from City A to B is 90 kilometers per hour. At constant speed, time is distance divided by velocity, so 450 km ÷ 90 km/h equals 5 hours one way. On return, speed becomes 112.5 km/h—25% faster—so 450 km ÷ 112.5 km/h = 4 hours. The 1-hour time difference confirms the calculation, showing how speed impacts travel planning.