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have the pacers ever made the finals - Decision Point

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 A chemical reaction requires 2.5 moles of substance A and 3.75 moles of substance B. If the molar mass of substance A is 58 g/mol and that of substance B is 93 g/mol, how many grams of each substance are needed for the reaction?

📌 First, find the mass of substance A: \(2.5 \, \text{moles} \times 58 \, \text{g/mol} = 145 \, \text{g}\).

📌 Then, find the mass of substance B: \(3.75 \, \text{moles} \times 93 \, \text{g/mol} = 348.75 \, \text{g}\).

📌 #### 145g of substance A and 348.75g of substance B

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So the solutions are \( z = i\sqrt{2} \) and \( z = -i\sqrt{2} \). Eac...
But wait — \( z^2 = -2 \) has exactly two solutions in \( \mathbb{C} \...
z = \sqrt{2}i, \quad z = -\sqrt{2}i
These are distinct and purely imaginary. The real part of each is 0.
Thus, the sum of the real parts is:
+ 0 = 0
Even though there are four roots? Let's double-check factorization.
Go back:
z^4 + 4z^2 + 4 = (z^2 + 2)^2 = 0
So indeed, \( (z^2 + 2)^2 = 0 \), so roots are \( z = \pm i\sqrt{2} \)...

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