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📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Improved system: 16 registers × 2 bytes each = <<16*2=32>>32 bytes

📌 Difference: 250 – 32 = <<250-32=218>>218 bytes

📌 But question asks how many bytes the ENIAC uses — assuming phrased as direct: ENIAC uses 250 bytes (20 digits × 10 registers × 0.055 ≈ 11)? Wait — standard interpretation: ENIAC’s memory equivalent:

📌 Use: 20 digits ≈ 20 × 4 = 80 bits per register → 8 bytes

📌 registers → 10 × 8 = 80 bytes per register? Too high.

📌 Better standard approximation: 1 digit ≈ 4 bits → 20 digits = 80 bits = 10 bytes per register → 10 × 10 = 100 bytes

📌 binary registers at 2 bytes each: 16 × 2 = 32 bytes

📌 Difference: 100 – 32 = <<100-32=68>>68 bytes more in ENIAC

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