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Home » First, we factor 2023 to find its divisors. Checking small prime numbers: - Decision Point

First, we factor 2023 to find its divisors. Checking small prime numbers: - Decision Point

📅 May 2, 2026 👤 scraface

May 02, 2026

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p'(1) = 4 imes 1^3 - 12 imes 1^2 + 12 imes 1 - 4 = 4 - 12 + 12 - 4...
Since \( p'(1) = 0 \), \( x = 1 \) is a root of multiplicity at least...
p''(x) = 12x^2 - 24x + 12
Evaluate \( p''(1) \):
p''(1) = 12 imes 1^2 - 24 imes 1 + 12 = 12 - 24 + 12 = 0
Compute the third derivative \( p'''(x) \):
p'''(x) = 24x - 24
p'''(1) = 24 imes 1 - 24 = 0
Compute the fourth derivative \( p^{(4)}(x) \):
p^{(4)}(x) = 24

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